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/*/*******************************************************************************
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** **
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** Jiedi(China nanjing)Ltd. **
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** 创建：丁宋涛 夏曹俊，此代码可用作为学习参考 **
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*******************************************************************************/
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/*****************************FILE INFOMATION***********************************
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**
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** Project : 算法设计与编程实践---基于leetcode的企业真题库
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** Contact : xiacaojun@qq.com
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** 博客 : http://blog.csdn.net/jiedichina
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** 视频课程 : 网易云课堂 http://study.163.com/u/xiacaojun
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腾讯课堂 https://jiedi.ke.qq.com/
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csdn学院 https://edu.csdn.net/course/detail/25037
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** 51cto学院 http://edu.51cto.com/lecturer/index/user_id-100013755.html
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** 老夏课堂 http://www.laoxiaketang.com
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**
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** 算法设计与编程实践---基于leetcode的企业真题库 课程群 ：296249312 加入群下载代码和交流
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** 微信公众号 : jiedi2007
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** 头条号 : 夏曹俊
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**
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*****************************************************************************
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//！！！！！！！！！ 算法设计与编程实践---基于leetcode的企业真题库 课程 QQ群：296249312 下载代码和交流*/
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/*
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* @lc app=leetcode.cn id=28 lang=cpp
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*
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* [28] 实现strStr()
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*/
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#include <string>
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using namespace std;
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class Solution {
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public:
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int strStr(string haystack, string needle) {
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if(needle.size() == 0)
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return 0;
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if(needle.size() >haystack.size())
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return -1;
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int i,j;
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i = 0;
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j = 0;
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for(i=0;i<haystack.size();i++){
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if(j == needle.size())
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return i - needle.size();
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if(haystack[i] == needle[j])
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j++;
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else{
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i -= j;
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j = 0;
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}
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}
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//用来单个字母的时候，j++，j=1,i=1
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if(j == needle.size())
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return i - needle.size();
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return -1;
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}
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};
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