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#include <bits/stdc++.h>
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#include <unordered_map>
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using namespace std;
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int main() {
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int N;
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cin >> N;
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vector<vector<int>> vb;
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for (int i = 0; i < N; i++) {
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int m;
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cin >> m;
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vector<int> v1;
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for (int j = 0; j < m; j++) {
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int c;
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cin >> c;
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v1.push_back(c);
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}
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vb.push_back(v1);
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}
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//1、从后向前找,找第一个大于0的数字,然后再从它开始向后,一直到头,加在一起
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//2、计算D
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int T = 0, D = 0, E = 0;
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vector<int> vShuGuo;
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int j;
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for (int i = 0; i < N; i++) {
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int pos;
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for (j = vb[i].size() - 1; j >= 0; j--) {
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if (vb[i][j] > 0) {
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pos = j;
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break;
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}
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}
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//计算T
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for (int k = pos; k < vb[i].size(); k++) {
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T += vb[i][k];
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}
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//计算D
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int sum = 0;
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for (int k = 0; k < pos; k++) {
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sum += vb[i][k];
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}
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if (sum > vb[i][pos]) {
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D++;
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vShuGuo.push_back(i + 1);
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}
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}
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//计算E的值
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unordered_map<int, int> _map;
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for (int i = 0; i < vShuGuo.size(); i++) {
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_map[vShuGuo[i]]++;
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}
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for (int i = 0; i < vShuGuo.size(); i++) {
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int next, nextnext;
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if (vShuGuo[i] == N) next = 1;
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else next = vShuGuo[i] + 1;
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if (next == N) nextnext = 1;
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else nextnext = next + 1;
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if (_map.count(next) > 0 && _map.count(nextnext) > 0) {
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E++;
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}
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}
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cout << T << " " << D << " " << E << endl;
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return 0;
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}
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/*
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4
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4 74 -7 -12 -5
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5 73 -8 -6 59 -4
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5 76 -5 -10 60 -2
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5 80 -6 -15 59 0
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5
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4 10 0 9 0
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4 10 -2 7 0
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2 10 0
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4 10 -3 5 0
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4 10 -1 8 0
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*/
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