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#include <bits/stdc++.h>
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using namespace std;
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const int N = 2e5 + 10, M = N << 1;
// 链式前向星
int e[M], h[N], idx, w[M], ne[M];
void add(int a, int b, int c = 0) {
e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
}
int f[N];
int g[N];
int c[N]; // 颜色
int n; // 节点数量
// 以1号节点为根跑一遍dfs,填充每个节点的cnt1-cnt2的最大值
void dfs1(int u, int fa) {
f[u] = c[u]; // 1白色-1黑色正好与 cnt1-cnt2一致,初始值加上了老头子自己的养老钱
for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
if (v == fa) continue;
dfs1(v, u);
f[u] += max(0, f[v]); // 如果我儿子给我,那我就拿着;如果我儿子不给我钱,或者管我要钱,我就不理它!
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}
}
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// 换根dp
void dfs2(int u, int fa) {
for (int i = h[u]; ~i; i = ne[i]) {
int v = e[i];
if (v == fa) continue;
int val = g[u] - max(f[v], 0);
g[v] = f[v] + max(val, 0);
dfs2(v, u);
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}
}
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int main() {
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// 初始化链式前向星
memset(h, -1, sizeof h);
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cin >> n;
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for (int i = 1; i <= n; i++) {
int x;
cin >> x;
c[i] = (x ? x : -1); // 白色c[i]=1黑色c[i]=-1
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}
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for (int i = 1; i < n; i++) {
int a, b;
cin >> a >> b;
add(a, b), add(b, a);
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}
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// 第一次dfs
dfs1(1, 0);
// 它们两个是一个意思
g[1] = f[1];
// 换根dp
dfs2(1, 0);
// 输出答案
for (int i = 1; i <= n; i++) printf("%d ", g[i]);
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return 0;
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}