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/*
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小马需要将N件物品从河的一岸搬运到河的另一岸,每次搬运的物品为1到3件。
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请问小马将N件物品全部搬运过去有多少种方案。
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例如:N=3,将3件物品全部搬运过去有4种方案:
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方案一:第一次搬运1件,第二次搬运1件,第三次搬运1件;
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方案二:第一次搬运1件,第二次搬运2件;
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方案三:第一次搬运2件,第二次搬运1件;
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方案四:一次搬运3件。
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*/
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#include <bits/stdc++.h>
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using namespace std;
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const int N = 110;
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int a[N];
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int res;
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int n;
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/**
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* @brief
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*
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* @param step 第几次
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* @param r 剩余件数
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*/
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void dfs(int u, int r) {
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if (r == 0) res++; //剩余为0,就得到一组答案
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//本轮运几件
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for (int i = 1; i <= 3; i++)
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if (r - i >= 0) dfs(u + 1, r - i);
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}
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int main() {
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cin >> n;
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dfs(0, n);
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printf("%d", res);
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return 0;
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}
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