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2 years ago
#include <bits/stdc++.h>
using namespace std;
const int N = 20010;
// 结构体记录原始输入
struct Node {
int x, y, e;
} g[N];
int n, m;
// 离散化静态数组+二分查找新位置
int b[N], bl;
int get(int x) {
return lower_bound(b, b + bl, x) - b;
}
// 带边权更新并查集模板
int p[N], d[N];
int find(int x) {
if (x == p[x]) return x;
int root = find(p[x]);
d[x] += d[p[x]];
return p[x] = root;
}
int main() {
scanf("%d %d", &n, &m);
n = 0; // 序列的长度没有用处我们只关心每个a,b范围内的数字1的个数
for (int i = 1; i < N; i++) p[i] = i; // 初始化并查集
for (int i = 1; i <= m; i++) {
int x, y;
char t[100];
scanf("%d %d %s", &x, &y, t);
g[i].x = x, g[i].y = y;
if (t[0] == 'e')
g[i].e = 0;
else
g[i].e = 1;
// 记录下来
b[bl++] = x, b[bl++] = y;
}
// 离散化去重
sort(b, b + 2 * m);
bl = unique(b, b + 2 * m) - b;
int res = m;
for (int i = 1; i <= m; i++) {
int a = g[i].x, b = g[i].y, e = g[i].e;
// 类前缀和
a = get(a - 1), b = get(b);
int t = 0; // 偶数个1
if (e == 1) t = 1; // 奇数个1
// 并查集
int pa = find(a), pb = find(b);
if (pa == pb) {
if (abs(d[a] - d[b]) % 2 != t) {
res = i - 1; // 最后一条正确的序号
break;
}
} else {
p[pa] = pb;
d[pa] = abs(d[a] - d[b] - t) % 2;
}
}
printf("%d\n", res);
return 0;
}