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#include <bits/stdc++.h>
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using namespace std;
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const int N = 6010;
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int happy[N]; // 快乐值
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int in[N]; // 入度
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int f[N][2]; // dp的状态结果数组
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int n;
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// 构建邻接表
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int h[N], e[N], ne[N], idx;
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void add(int a, int b) {
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e[idx] = b, ne[idx] = h[a], h[a] = idx++;
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}
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// 通过深度优先搜索,对树进行遍历
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void dfs(int u) {
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for (int i = h[u]; ~i; i = ne[i]) {
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int v = e[i];
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dfs(v); // 继续探索它的孩子,它的值是由它的孩子来决定的
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f[u][1] += f[v][0]; // 它选择了,它的孩子就不能再选
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f[u][0] += max(f[v][0], f[v][1]); // 它不选择,那么它的每一个孩子,都是可以选择或者不选择的
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}
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// 不管是不是叶子结点,都会产生happy[u]的价值
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f[u][1] += happy[u];
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}
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int main() {
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// 邻接表表头初始化
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memset(h, -1, sizeof h);
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cin >> n;
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for (int i = 1; i <= n; i++) cin >> happy[i];
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// 读入树
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for (int i = 1; i < n; i++) { // n-1条边
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int x, y;
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cin >> x >> y;
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add(y, x);
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in[x]++; // 记录入度,因为需要找出大boss
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}
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// 从1开始找根结点
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int root = 1;
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while (in[root]) root++; // 找到根结点,入度为0
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// 递归
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dfs(root);
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// 取两个
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printf("%d\n", max(f[root][0], f[root][1]));
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return 0;
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}
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