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#include <bits/stdc++.h>
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using namespace std;
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const int N = 1e5 + 10;
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int a[N]; //原始数组
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int f[N]; //递推结果数组
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/*
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记忆化搜索
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状态转移方程是 前i个数 = max(前i-1个数,前i-2个数 +第i个数)
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平时写一下搜索还是挺好的。 (比Dp还快 2ms)
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O(n)
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*/
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int dfs(int u) {
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if (u <= 0) return 0;//注意一下这个边界
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if (f[u]) return f[u];//记忆化搜索的灵魂
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return f[u] = max(dfs(u - 1), dfs(u - 2) + a[u]);
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}
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int main() {
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int T, n;
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scanf("%d", &T);
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while (T--) {
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scanf("%d", &n);
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//每次重置一下结果数组
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memset(f, 0, sizeof f);
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for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
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printf("%d\n", dfs(n));
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}
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return 0;
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}
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