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#include <bits/stdc++.h>
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using namespace std;
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const int N = 100100;
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int b[2 * N]; // key,value:第几个端点,坐标值
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int idx; // 用于维护数组b的游标
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int n; // 共几个区间
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int res = 1; // 全放到一个组中,最小,默认值1
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int main() {
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// n个区间
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cin >> n;
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for (int i = 1; i <= n; i++) {
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int l, r;
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cin >> l >> r;
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b[idx++] = l * 2 + 1; // 标记左端点为奇数;同比放大2倍,还不影响排序的位置,牛~
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b[idx++] = r * 2; // 标记右端点为偶数;同比放大2倍,还不影响排序的位置,牛~
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}
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// 将所有端点放在一起排序,由小到大
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sort(b, b + idx);
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int t = 0;
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for (int i = 0; i < idx; i++) {
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if (b[i] % 2)
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t++; // 左端点
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else
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t--; // 右端点
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res = max(res, t); // 动态计算什么时间点时,出现左的个数减去右的个数差最大,就是冲突最多的时刻
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}
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// 输出结果
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cout << res << endl;
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return 0;
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}
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