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#include <bits/stdc++.h>
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using namespace std;
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//没仔细研究为什么贪心是对的
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/*
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思路：只能切一条生成树上的边，一个比较直观的想法是只切度数为1的点的那条边，然后枚举这个叶子和外面连接的边数即可
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*/
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const int maxn = 20000 + 7;
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#define inf 1e9
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vector<int> e[maxn];
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int vis[maxn];
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int deg[maxn], degg[maxn];
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int n, m;
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int main() {
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int T, cas = 1;
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scanf("%d", &T);
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while (T--) {
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memset(deg, 0, sizeof(deg));
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memset(degg, 0, sizeof(degg));
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memset(vis, 0, sizeof(vis));
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printf("Case #%d: ", cas++);
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scanf("%d%d", &n, &m);
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for (int i = 0; i < n - 1; i++) {
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int u, v;
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scanf("%d%d", &u, &v);
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deg[u]++;
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deg[v]++;
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if (deg[u] > 1) vis[u] = 1;
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if (deg[v] > 1) vis[v] = 1;
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}
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for (int i = 0; i < m - n + 1; i++) {
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int u, v;
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scanf("%d%d", &u, &v);
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degg[u]++;
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degg[v]++;
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}
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int ans = inf;
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for (int i = 1; i <= n; i++)
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if (!vis[i]) ans = min(ans, deg[i] + degg[i]);
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printf("%d\n", ans);
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}
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}
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