You can not select more than 25 topics
Topics must start with a letter or number, can include dashes ('-') and can be up to 35 characters long.
|
|
|
|
#include <bits/stdc++.h>
|
|
|
|
|
|
|
|
|
|
using namespace std;
|
|
|
|
|
const int N = 100010, M = 200010;
|
|
|
|
|
const int INF = 0x3f3f3f3f;
|
|
|
|
|
int ans = INF;
|
|
|
|
|
bool st[N];
|
|
|
|
|
int n;
|
|
|
|
|
int h[N], e[M], ne[M], idx;
|
|
|
|
|
void add(int a, int b) {
|
|
|
|
|
e[idx] = b, ne[idx] = h[a], h[a] = idx++;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
int dfs(int u) {
|
|
|
|
|
st[u] = 1;
|
|
|
|
|
int sum = 1;
|
|
|
|
|
int res = 0;
|
|
|
|
|
for (int i = h[u]; ~i; i = ne[i]) {
|
|
|
|
|
int v = e[i];
|
|
|
|
|
if (!st[v]) {
|
|
|
|
|
int s = dfs(v); // v子树有多少个节点
|
|
|
|
|
sum += s; // 儿子们的节点个数累加和,再加自己的1,就是u子树的节点个数sum和
|
|
|
|
|
res = max(res, s); // 猴子选大王
|
|
|
|
|
}
|
|
|
|
|
}
|
|
|
|
|
res = max(res, n - sum); // 套路:除了自己的所有猴子,还要考虑反向子树
|
|
|
|
|
ans = min(ans, res); // 最大中选最小,就是树的重心
|
|
|
|
|
return sum;
|
|
|
|
|
}
|
|
|
|
|
|
|
|
|
|
int main() {
|
|
|
|
|
memset(h, -1, sizeof h);
|
|
|
|
|
cin >> n; // n个顶点
|
|
|
|
|
for (int i = 1; i < n; i++) { // n-1条边
|
|
|
|
|
int a, b;
|
|
|
|
|
cin >> a >> b;
|
|
|
|
|
add(a, b), add(b, a);
|
|
|
|
|
}
|
|
|
|
|
dfs(1);
|
|
|
|
|
cout << ans << endl;
|
|
|
|
|
return 0;
|
|
|
|
|
}
|