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#include <bits/stdc++.h>
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using namespace std;
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const int N = 100010;
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int n, m;
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int a[N];
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// 树状数组模板
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typedef long long LL;
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#define lowbit(x) (x & -x)
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int c[N];
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void add(int x, int d) {
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for (int i = x; i < N; i += lowbit(i)) c[i] += d;
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}
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LL sum(int x) {
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LL res = 0;
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for (int i = x; i; i -= lowbit(i)) res += c[i];
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return res;
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}
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int main() {
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scanf("%d %d", &n, &m);
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for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
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// 方法1:也可以这么做,但是方法比较笨拙
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// 树状数组初始化,保存差分值
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// for (int i = 1; i <= n; i++) add(i, a[i] - a[i - 1]);
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while (m--) {
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char op[2];
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scanf("%s", op);
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if (op[0] == 'C') { // 修改
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int l, r, d;
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scanf("%d %d %d", &l, &r, &d);
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// 差分,在l处加上d,在r+1位置减去d
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add(l, d), add(r + 1, -d);
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} else {
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int l;
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scanf("%d", &l);
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// 方法1
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// printf("%lld\n", sum(l)); // 求前缀和
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// 推荐方法
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printf("%lld\n", a[l] + sum(l)); // 求前缀和
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}
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}
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return 0;
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}
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