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#include <bits/stdc++.h>
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using namespace std;
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const int N = 200010;
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const int M = 2000010; //文本串长度
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int f[N];
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char s[N];
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char T[M];
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int tr[N][26], idx, ne[N], id[N];
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void insert(char *s, int x) {
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int p = 0;
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for (int i = 0; s[i]; i++) {
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int t = s[i] - 'a';
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if (!tr[p][t]) tr[p][t] = ++idx;
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p = tr[p][t];
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}
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id[x] = p;
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}
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//构建AC自动机
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int q[N], hh, tt = -1;
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void bfs() {
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for (int i = 0; i < 26; i++)
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if (tr[0][i]) q[++tt] = tr[0][i];
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while (hh <= tt) {
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int t = q[hh++];
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for (int i = 0; i < 26; ++i) {
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if (tr[t][i]) {
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ne[tr[t][i]] = tr[ne[t]][i];
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q[++tt] = tr[t][i];
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} else
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tr[t][i] = tr[ne[t]][i];
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}
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}
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}
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void query(char *s) {
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int p = 0;
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for (int i = 0; s[i]; i++) { // 枚举文本串每一个字符
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int t = s[i] - 'a'; // 字符映射的数字t,可以理解为边
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p = tr[p][t]; // 走进去,到达的位置替换p
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f[p]++; // 标识此位置有人走过,记录走的次数
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}
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}
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int main() {
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//加快读入
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ios::sync_with_stdio(false), cin.tie(0);
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int n;
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cin >> n;
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for (int i = 1; i <= n; i++) {
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cin >> s;
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insert(s, i);
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}
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//构建AC自动机
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bfs();
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//文本串
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cin >> T;
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query(T);
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for (int i = idx; i; i--) f[ne[q[i]]] += f[q[i]]; //一路向上,计算叠加值
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//输出
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for (int i = 1; i <= n; i++) printf("%d\n", f[id[i]]);
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return 0;
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}
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