python/RuMenJingDian/LiTi/P_3_3.cpp

#include <bits/stdc++.h>

using namespace std;


const char *rev = "A   3  HILJM O   2TUVWXY51SE Z  8 ";
const char *msg[] = {"not a palindrome",
                     "a regular palindrome",
                     "a mirrored string",
                     "a mirrored palindrome"};

char r(char ch) {
    if (isalpha(ch)) return rev[ch - 'A'];//如果是字符，那么计算出它所在的索引号，比如是A，那么索引号是0
    else return rev[ch - '0' + 25]; //如果是数字，那么-'0'就是0，+25就是数字对应的索引号
}

int main() {
    ios::sync_with_stdio(false); //读入输出优化的强迫症
    char s[30];
    while (scanf("%s", s) == 1) {
        int len = strlen(s);
        int p = 1, m = 1;
        for (int i = 0; i < (len + 1) / 2; i++) {
            //折半去看
            if (s[i] != s[len - 1 - i]) p = 0;
            if (r(s[i]) != s[len - 1 - i]) m = 0;
        }
        //这个msg的数组索引用的好，有点二进制的意思~
        printf("%s-- is %s.\n\n", s, msg[m * 2 + p]);
    }
    return 0;
}