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dsProject/dsLightRag/YunXiao/target/《万有引力定律》基础题(简单难度)5.md
2025-08-27 16:40:46 +08:00

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> 1\.
> 观察"神舟十号"在圆轨道上的运动发现每经过时间2*t*通过的弧长为*L*,该弧长对应的圆心角为*θ*(弧度),如图所示,已知引力常量为*G*,由此可推导出地球的质量为(  )
>
> ![](https://obs.cn-north-1.myhuaweicloud.com/dsideal/HuangHai/YunXiao/e6d40f5e-c41f-4ff3-abcd-45b96c6fa610.png){width="4.222222222222222in"
> height="1.6666666666666667in"}
>
> A ![](https://obs.cn-north-1.myhuaweicloud.com/dsideal/HuangHai/YunXiao/be641f95-b81c-4e49-9cca-600f8d1fcf71.png){width="0.4895833333333333in"
> height="0.4583333333333333in"} B
> ![](https://obs.cn-north-1.myhuaweicloud.com/dsideal/HuangHai/YunXiao/86495819-c986-4f9b-a545-eb6b1cef0bb0.png){width="0.375in" height="0.4583333333333333in"}
>
> C ![](https://obs.cn-north-1.myhuaweicloud.com/dsideal/HuangHai/YunXiao/0936fe78-3f86-481f-87c1-cdc838364bcb.png){width="0.4895833333333333in"
> height="0.4270833333333333in"} D
> ![](https://obs.cn-north-1.myhuaweicloud.com/dsideal/HuangHai/YunXiao/b810b64c-7d90-4f1f-b5e7-c8e66bdddfbd.png){width="0.40625in"
> height="0.4583333333333333in"}
>
> 【难度】\
> 简单
>
> 【答案】
>
> A
>
> 【解析】
>
> 【解答】根据弧长和半径的关系,可得轨道半径为
> ![](https://obs.cn-north-1.myhuaweicloud.com/dsideal/HuangHai/YunXiao/1cecafb6-db83-4744-b154-b8e6d4ed3dae.png){width="0.4583333333333333in"
> height="0.4270833333333333in"}
>
> 根据万有引力提供向心力有\
>
> ![](https://obs.cn-north-1.myhuaweicloud.com/dsideal/HuangHai/YunXiao/2cad0ba1-bd6a-403f-9f9a-d8d3c5efd288.png){width="1.6979166666666667in"
> height="0.6979166666666666in"}
>
> 联立解的,地球的质量
>
> ![](https://obs.cn-north-1.myhuaweicloud.com/dsideal/HuangHai/YunXiao/5c01fb31-9af7-45a6-8409-3dab87b7a44f.png){width="0.8333333333333334in"
> height="0.4583333333333333in"}
>
> 所以A正确BCD错误
>
> 故选A。
>
> 【分析】本题考查圆周运动角速度和线速度的计算以及万有引力提供向心力的计算。
>
> 【关联章节】第七章 万有引力与宇宙航行第七章 万有引力与宇宙航行 \> 2.
> 万有引力定律;
>
> 【关联知识点】经典力学的成就与局限性 \> 万有引力定律;
>
> 【关联素养点】暂无数据
>
> 【关联关键能力】暂无数据