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HuangHai 2 weeks ago
parent a1a5418f21
commit e3bffd86d1
26 changed files with 556 additions and 20 deletions
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2
dsLightRag/Doc/8、图数据库DozerDb.md
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@ -1,3 +1 @@
https://dozerdb.org/
https://milvus.io/

2
dsLightRag/T1_Train.py
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@ -5,7 +5,7 @@ from Util.LightRagUtil import configure_logging, initialize_rag
import os
# 数学
KEMU = 'Chemistry' # Chinese,Math,Chemistry
KEMU = 'JiHe' # Chinese,Math,Chemistry,JiHe
# 组装文件路径
WORKING_DIR = "./Topic/" + KEMU

6
dsLightRag/T2_Query.py
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@ -8,10 +8,12 @@ data = [
# {"NAME": "Chemistry", "Q": "硝酸光照分解的化学反应方程式是什么", "ChineseName": "化学"},
{"NAME": "Chemistry", "Q": "氢气与氧气燃烧的现象", "ChineseName": "化学"},
{"NAME": "Math", "Q": "氧化铁与硝酸的化学反应方程式是什么", "ChineseName": "数学"},
{"NAME": "Chinese", "Q": "氧化铁与硝酸的化学反应方程式是什么", "ChineseName": "语文"}]
{"NAME": "Chinese", "Q": "氧化铁与硝酸的化学反应方程式是什么", "ChineseName": "语文"},
{"NAME": "JiHe", "Q": "三角形两边之和大于第三边的证明", "ChineseName": "几何"}
]
# 准备查询的科目
KEMU = "Chemistry"
KEMU = "JiHe" # Chemistry JiHe
# 查找索引号
idx = [i for i, d in enumerate(data) if d["NAME"] == KEMU][0]

265
dsLightRag/Topic/Chemistry/graph_chunk_entity_relation.graphml
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@ -0,0 +1,265 @@
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<data key="d0">Photodecomposition</data>
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dsLightRag/Topic/Chemistry/kv_store_doc_status.json
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{
"doc-e4dee9f72e6c899fd70a04b77c38d8d0": {
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"status": "processed",
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"content": "硝酸光照分解的方程式\n$$4HNO_{3}overset{overset{}{{Delta}}}{=}4NO_{2} uparrow + O_{2} uparrow + 2HO_{2}$$\n氧化铁与硝酸的加热反应方程式\n$$FeO + 4HNO_{3}overset{overset{}{{Delta}}}{=}Fe(NO_{3})_{3} + 2H_{2} uparrow + NO_{2} uparrow$$\n氢气与氧气燃烧的现象如下图所示：\n$$2H_{2} + O_{2}overset{overset{}{text{燃烧}}}{=}2H_{2}O$$\n![](./Images/500a35d1483c4b9d934ff584073c6590/media/image1.png)",
"content": "硝酸光照分解的方程式\n$$4HNO_{3}overset{overset{}{{Delta}}}{=}4NO_{2} uparrow + O_{2} uparrow + 2HO_{2}$$\n氧化铁与硝酸的加热反应方程式\n$$FeO + 4HNO_{3}overset{overset{}{{Delta}}}{=}Fe(NO_{3})_{3} + 2H_{2} uparrow + NO_{2} uparrow$$\n氢气与氧气燃烧的现象如下图所示：\n$$2H_{2} + O_{2}overset{overset{}{text{燃烧}}}{=}2H_{2}O$$\n![](./Images/c8c0221648af480699a364fd50cbbeb6/media/image1.png)",
"content_summary": "硝酸光照分解的方程式\n$$4HNO_{3}overset{overset{}{{Delta}}}{=}4NO_{2} uparrow + O_{2} uparrow + 2HO_{2}$$\n氧化铁与硝酸的加热反应方程式\n$$FeO + 4HNO_{3}overset{overset{}{{Delta}}}{=}Fe(NO_{3})_{3} + 2H_{2} uparrow + NO_{2} uparrow$$\n氢气与氧气燃烧的现象如下图所示：\n$$2H_{2} + O_{2}overset{ov...",
"content_length": 344,
"created_at": "2025-07-11T00:33:18.094744+00:00",
"updated_at": "2025-07-11T00:37:04.761470+00:00",
"created_at": "2025-07-11T03:42:25.898814+00:00",
"updated_at": "2025-07-11T03:43:17.438419+00:00",
"file_path": "unknown_source"
}
}

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dsLightRag/Topic/Chemistry/kv_store_full_docs.json
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{
"doc-e4dee9f72e6c899fd70a04b77c38d8d0": {
"content": "硝酸光照分解的方程式\n$$4HNO_{3}overset{overset{}{{Delta}}}{=}4NO_{2} uparrow + O_{2} uparrow + 2HO_{2}$$\n氧化铁与硝酸的加热反应方程式\n$$FeO + 4HNO_{3}overset{overset{}{{Delta}}}{=}Fe(NO_{3})_{3} + 2H_{2} uparrow + NO_{2} uparrow$$\n氢气与氧气燃烧的现象如下图所示：\n$$2H_{2} + O_{2}overset{overset{}{text{燃烧}}}{=}2H_{2}O$$\n![](./Images/500a35d1483c4b9d934ff584073c6590/media/image1.png)"
"doc-d0c3bf985a3b3b903e2fb35515fdff1e": {
"content": "硝酸光照分解的方程式\n$$4HNO_{3}overset{overset{}{{Delta}}}{=}4NO_{2} uparrow + O_{2} uparrow + 2HO_{2}$$\n氧化铁与硝酸的加热反应方程式\n$$FeO + 4HNO_{3}overset{overset{}{{Delta}}}{=}Fe(NO_{3})_{3} + 2H_{2} uparrow + NO_{2} uparrow$$\n氢气与氧气燃烧的现象如下图所示：\n$$2H_{2} + O_{2}overset{overset{}{text{燃烧}}}{=}2H_{2}O$$\n![](./Images/c8c0221648af480699a364fd50cbbeb6/media/image1.png)"
}
}

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dsLightRag/Topic/Chemistry/kv_store_llm_response_cache.json
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dsLightRag/Topic/Chemistry/kv_store_text_chunks.json
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"content": "硝酸光照分解的方程式\n$$4HNO_{3}overset{overset{}{{Delta}}}{=}4NO_{2} uparrow + O_{2} uparrow + 2HO_{2}$$\n氧化铁与硝酸的加热反应方程式\n$$FeO + 4HNO_{3}overset{overset{}{{Delta}}}{=}Fe(NO_{3})_{3} + 2H_{2} uparrow + NO_{2} uparrow$$\n氢气与氧气燃烧的现象如下图所示：\n$$2H_{2} + O_{2}overset{overset{}{text{燃烧}}}{=}2H_{2}O$$\n![](./Images/500a35d1483c4b9d934ff584073c6590/media/image1.png)",
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"content": "硝酸光照分解的方程式\n$$4HNO_{3}overset{overset{}{{Delta}}}{=}4NO_{2} uparrow + O_{2} uparrow + 2HO_{2}$$\n氧化铁与硝酸的加热反应方程式\n$$FeO + 4HNO_{3}overset{overset{}{{Delta}}}{=}Fe(NO_{3})_{3} + 2H_{2} uparrow + NO_{2} uparrow$$\n氢气与氧气燃烧的现象如下图所示：\n$$2H_{2} + O_{2}overset{overset{}{text{燃烧}}}{=}2H_{2}O$$\n![](./Images/c8c0221648af480699a364fd50cbbeb6/media/image1.png)",
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dsLightRag/Topic/Chemistry/vdb_chunks.json
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dsLightRag/Topic/Chemistry/vdb_entities.json
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dsLightRag/Topic/Chemistry/vdb_relationships.json
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dsLightRag/Topic/JiHe/graph_chunk_entity_relation.graphml
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<?xml version='1.0' encoding='utf-8'?>
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{
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"content": "三角形三边关系的证明\n证明方法如下：\n作下图所示的三角形ABC。在三角形ABC中，[三角不等式](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E4%B8%89%E8%A7%92%E4%B8%8D%E7%AD%89%E5%BC%8F&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9zZXJ2ZXIiLCJleHAiOjE3NTIzNzg0NDAsInEiOiLkuInop5LkuI3nrYnlvI8iLCJ6aGlkYV9zb3VyY2UiOiJlbnRpdHkiLCJjb250ZW50X2lkIjoyNDgyMTc4NTAsImNvbnRlbnRfdHlwZSI6IkFydGljbGUiLCJtYXRjaF9vcmRlciI6MSwiemRfdG9rZW4iOm51bGx9.rH6r8SvGmu-I9piEsmZfg2HjbXzUduYclZ2jfA3jZRs&zhida_source=entity)可以表示为|AB|+|BC|＞|AC|。\n![](./Images/7a1f3e68c9234e8d87deca2b32a13f20/media/image1.png)\nheight=\"2.8183694225721783in\"}\n①延长直线AB至点D，并使|BD|=|BC|，连接|DC|，那么三角形BCD为等腰三角形。所以∠BDC=∠BCD。\n②记它们均为α，根据[欧几里得第五公理](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E6%AC%A7%E5%87%A0%E9%87%8C%E5%BE%97%E7%AC%AC%E4%BA%94%E5%85%AC%E7%90%86&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9zZXJ2ZXIiLCJleHAiOjE3NTIzNzg0NDAsInEiOiLmrKflh6Dph4zlvpfnrKzkupTlhaznkIYiLCJ6aGlkYV9zb3VyY2UiOiJlbnRpdHkiLCJjb250ZW50X2lkIjoyNDgyMTc4NTAsImNvbnRlbnRfdHlwZSI6IkFydGljbGUiLCJtYXRjaF9vcmRlciI6MSwiemRfdG9rZW4iOm51bGx9.ltcWsMYJv-ZzcuBaSjYN69JC8hnIyPMFsfhIlum4yqc&zhida_source=entity)，∠ACD大于角∠ADC(α)。\n③由于∠ACD的对边为AD，∠ADC(α)的对边为AC，所以根据大角对大边([几何原本](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E5%87%A0%E4%BD%95%E5%8E%9F%E6%9C%AC&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9zZXJ2ZXIiLCJleHAiOjE3NTIzNzg0NDAsInEiOiLlh6DkvZXljp_mnKwiLCJ6aGlkYV9zb3VyY2UiOiJlbnRpdHkiLCJjb250ZW50X2lkIjoyNDgyMTc4NTAsImNvbnRlbnRfdHlwZSI6IkFydGljbGUiLCJtYXRjaF9vcmRlciI6MSwiemRfdG9rZW4iOm51bGx9.Q1rCY0S2bj5Dwp3Fg7xb_VSFESz2_pCUETDybnHANvo&zhida_source=entity)中的命题19)就可以得到|AB|+|BC|=|AB|+|BD|=|AD|＞|AC|。",
"content_summary": "三角形三边关系的证明\n证明方法如下：\n作下图所示的三角形ABC。在三角形ABC中，[三角不等式](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E4%B8%89%E8%A7%92%E4%B8%8D%E7%AD%89%E5%BC%8F&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9z...",
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{
"doc-a5e3dacee89618f913c4948b6ffe64ec": {
"content": "三角形三边关系的证明\n证明方法如下：\n作下图所示的三角形ABC。在三角形ABC中，[三角不等式](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E4%B8%89%E8%A7%92%E4%B8%8D%E7%AD%89%E5%BC%8F&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9zZXJ2ZXIiLCJleHAiOjE3NTIzNzg0NDAsInEiOiLkuInop5LkuI3nrYnlvI8iLCJ6aGlkYV9zb3VyY2UiOiJlbnRpdHkiLCJjb250ZW50X2lkIjoyNDgyMTc4NTAsImNvbnRlbnRfdHlwZSI6IkFydGljbGUiLCJtYXRjaF9vcmRlciI6MSwiemRfdG9rZW4iOm51bGx9.rH6r8SvGmu-I9piEsmZfg2HjbXzUduYclZ2jfA3jZRs&zhida_source=entity)可以表示为|AB|+|BC|＞|AC|。\n![](./Images/7a1f3e68c9234e8d87deca2b32a13f20/media/image1.png)\nheight=\"2.8183694225721783in\"}\n①延长直线AB至点D，并使|BD|=|BC|，连接|DC|，那么三角形BCD为等腰三角形。所以∠BDC=∠BCD。\n②记它们均为α，根据[欧几里得第五公理](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E6%AC%A7%E5%87%A0%E9%87%8C%E5%BE%97%E7%AC%AC%E4%BA%94%E5%85%AC%E7%90%86&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9zZXJ2ZXIiLCJleHAiOjE3NTIzNzg0NDAsInEiOiLmrKflh6Dph4zlvpfnrKzkupTlhaznkIYiLCJ6aGlkYV9zb3VyY2UiOiJlbnRpdHkiLCJjb250ZW50X2lkIjoyNDgyMTc4NTAsImNvbnRlbnRfdHlwZSI6IkFydGljbGUiLCJtYXRjaF9vcmRlciI6MSwiemRfdG9rZW4iOm51bGx9.ltcWsMYJv-ZzcuBaSjYN69JC8hnIyPMFsfhIlum4yqc&zhida_source=entity)，∠ACD大于角∠ADC(α)。\n③由于∠ACD的对边为AD，∠ADC(α)的对边为AC，所以根据大角对大边([几何原本](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E5%87%A0%E4%BD%95%E5%8E%9F%E6%9C%AC&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9zZXJ2ZXIiLCJleHAiOjE3NTIzNzg0NDAsInEiOiLlh6DkvZXljp_mnKwiLCJ6aGlkYV9zb3VyY2UiOiJlbnRpdHkiLCJjb250ZW50X2lkIjoyNDgyMTc4NTAsImNvbnRlbnRfdHlwZSI6IkFydGljbGUiLCJtYXRjaF9vcmRlciI6MSwiemRfdG9rZW4iOm51bGx9.Q1rCY0S2bj5Dwp3Fg7xb_VSFESz2_pCUETDybnHANvo&zhida_source=entity)中的命题19)就可以得到|AB|+|BC|=|AB|+|BD|=|AD|＞|AC|。"
}
}

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{
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"content": "三角形三边关系的证明\n证明方法如下：\n作下图所示的三角形ABC。在三角形ABC中，[三角不等式](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E4%B8%89%E8%A7%92%E4%B8%8D%E7%AD%89%E5%BC%8F&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9zZXJ2ZXIiLCJleHAiOjE3NTIzNzg0NDAsInEiOiLkuInop5LkuI3nrYnlvI8iLCJ6aGlkYV9zb3VyY2UiOiJlbnRpdHkiLCJjb250ZW50X2lkIjoyNDgyMTc4NTAsImNvbnRlbnRfdHlwZSI6IkFydGljbGUiLCJtYXRjaF9vcmRlciI6MSwiemRfdG9rZW4iOm51bGx9.rH6r8SvGmu-I9piEsmZfg2HjbXzUduYclZ2jfA3jZRs&zhida_source=entity)可以表示为|AB|+|BC|＞|AC|。\n![](./Images/7a1f3e68c9234e8d87deca2b32a13f20/media/image1.png)\nheight=\"2.8183694225721783in\"}\n①延长直线AB至点D，并使|BD|=|BC|，连接|DC|，那么三角形BCD为等腰三角形。所以∠BDC=∠BCD。\n②记它们均为α，根据[欧几里得第五公理](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E6%AC%A7%E5%87%A0%E9%87%8C%E5%BE%97%E7%AC%AC%E4%BA%94%E5%85%AC%E7%90%86&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9zZXJ2ZXIiLCJleHAiOjE3NTIzNzg0NDAsInEiOiLmrKflh6Dph4zlvpfnrKzkupTlhaznkIYiLCJ6aGlkYV9zb3VyY2UiOiJlbnRpdHkiLCJjb250ZW50X2lkIjoyNDgyMTc4NTAsImNvbnRlbnRfdHlwZSI6IkFydGljbGUiLCJtYXRjaF9vcmRlciI6MSwiemRfdG9rZW4iOm51bGx9.ltcWsMYJv-ZzcuBaSjYN69JC8hnIyPMFsfhIlum4yqc&zhida_source=entity)，∠ACD大于角∠ADC(α)。\n③由于∠ACD的对边为AD，∠ADC(α)的对边为AC，所以根据大角对大边([几何原本](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E5%87%A0%E4%BD%95%E5%8E%9F%E6%9C%AC&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9zZXJ2ZXIiLCJleHAiOjE3NTIzNzg0NDAsInEiOiLlh6DkvZXljp_mnKwiLCJ6aGlkYV9zb3VyY2UiOiJlbnRpdHkiLCJjb250ZW50X2lkIjoyNDgyMTc4NTAsImNvbnRlbnRfdHlwZSI6IkFydGljbGUiLCJtYXRjaF9vcmRlciI6MSwiemRfdG9rZW4iOm51bGx9.Q1rCY0S2bj5Dwp3Fg7xb_VSFESz2_pCUETDybnHANvo&zhida_source=entity)中的命题19)就可以得到|AB|+|BC|=|AB|+|BD|=|AD|＞|AC|。",
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@ -4,4 +4,4 @@ $$4HNO_{3}\overset{\overset{}{{\Delta}}}{=}4NO_{2} \uparrow + O_{2} \uparrow + 2
$$FeO + 4HNO_{3}\overset{\overset{}{{\Delta}}}{=}Fe(NO_{3})_{3} + 2H_{2} \uparrow + NO_{2} \uparrow$$
氢气与氧气燃烧的现象如下图所示：
$$2H_{2} + O_{2}\overset{\overset{}{\text{燃烧}}}{=}2H_{2}O$$
![](./Images/500a35d1483c4b9d934ff584073c6590/media/image1.png)
![](./Images/c8c0221648af480699a364fd50cbbeb6/media/image1.png)

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三角形三边关系的证明
证明方法如下：
作下图所示的三角形ABC。在三角形ABC中，[三角不等式](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E4%B8%89%E8%A7%92%E4%B8%8D%E7%AD%89%E5%BC%8F&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9zZXJ2ZXIiLCJleHAiOjE3NTIzNzg0NDAsInEiOiLkuInop5LkuI3nrYnlvI8iLCJ6aGlkYV9zb3VyY2UiOiJlbnRpdHkiLCJjb250ZW50X2lkIjoyNDgyMTc4NTAsImNvbnRlbnRfdHlwZSI6IkFydGljbGUiLCJtYXRjaF9vcmRlciI6MSwiemRfdG9rZW4iOm51bGx9.rH6r8SvGmu-I9piEsmZfg2HjbXzUduYclZ2jfA3jZRs&zhida_source=entity)可以表示为\|AB\|+\|BC\|＞\|AC\|。
![](./Images/7a1f3e68c9234e8d87deca2b32a13f20/media/image1.png)
height="2.8183694225721783in"}\
①延长直线AB至点D，并使\|BD\|=\|BC\|，连接\|DC\|，那么三角形BCD为等腰三角形。所以∠BDC=∠BCD。
②记它们均为α，根据[欧几里得第五公理](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E6%AC%A7%E5%87%A0%E9%87%8C%E5%BE%97%E7%AC%AC%E4%BA%94%E5%85%AC%E7%90%86&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9zZXJ2ZXIiLCJleHAiOjE3NTIzNzg0NDAsInEiOiLmrKflh6Dph4zlvpfnrKzkupTlhaznkIYiLCJ6aGlkYV9zb3VyY2UiOiJlbnRpdHkiLCJjb250ZW50X2lkIjoyNDgyMTc4NTAsImNvbnRlbnRfdHlwZSI6IkFydGljbGUiLCJtYXRjaF9vcmRlciI6MSwiemRfdG9rZW4iOm51bGx9.ltcWsMYJv-ZzcuBaSjYN69JC8hnIyPMFsfhIlum4yqc&zhida_source=entity)，∠ACD大于角∠ADC(α)。
③由于∠ACD的对边为AD，∠ADC(α)的对边为AC，所以根据大角对大边([几何原本](https://zhida.zhihu.com/search?content_id=248217850&content_type=Article&match_order=1&q=%E5%87%A0%E4%BD%95%E5%8E%9F%E6%9C%AC&zd_token=eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJpc3MiOiJ6aGlkYV9zZXJ2ZXIiLCJleHAiOjE3NTIzNzg0NDAsInEiOiLlh6DkvZXljp_mnKwiLCJ6aGlkYV9zb3VyY2UiOiJlbnRpdHkiLCJjb250ZW50X2lkIjoyNDgyMTc4NTAsImNvbnRlbnRfdHlwZSI6IkFydGljbGUiLCJtYXRjaF9vcmRlciI6MSwiemRfdG9rZW4iOm51bGx9.Q1rCY0S2bj5Dwp3Fg7xb_VSFESz2_pCUETDybnHANvo&zhida_source=entity)中的命题19)就可以得到\|AB\|+\|BC\|=\|AB\|+\|BD\|=\|AD\|＞\|AC\|。
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