diff --git a/dsLightRag/Config/Config.py b/dsLightRag/Config/Config.py
index 6bcc5fb5..8b5e93cc 100644
--- a/dsLightRag/Config/Config.py
+++ b/dsLightRag/Config/Config.py
@@ -15,6 +15,10 @@ EMBED_BASE_URL = "https://api.siliconflow.cn/v1"
 EMBED_DIM = 1024
 EMBED_MAX_TOKEN_SIZE = 8192
 
+# 视觉模型
+VISION_API_KEY = "sk-pbqibyjwhrgmnlsmdygplahextfaclgnedetybccknxojlyl"
+VISION_BASE_URL = "https://api.siliconflow.cn/v1/chat/completions"
+VISION_MODEL_NAME = "GLM-4.1V-9B-Thinking"
 
 NEO4J_URI = "bolt://localhost:7687"
 NEO4J_USERNAME = "neo4j"
diff --git a/dsLightRag/Config/__pycache__/Config.cpython-310.pyc b/dsLightRag/Config/__pycache__/Config.cpython-310.pyc
index 02dba342..7b37be29 100644
Binary files a/dsLightRag/Config/__pycache__/Config.cpython-310.pyc and b/dsLightRag/Config/__pycache__/Config.cpython-310.pyc differ
diff --git a/dsLightRag/Config/__pycache__/__init__.cpython-310.pyc b/dsLightRag/Config/__pycache__/__init__.cpython-310.pyc
index a118d2da..ce15d799 100644
Binary files a/dsLightRag/Config/__pycache__/__init__.cpython-310.pyc and b/dsLightRag/Config/__pycache__/__init__.cpython-310.pyc differ
diff --git a/dsLightRag/ShiTi/Res/整理后的结果.md b/dsLightRag/ShiTi/Res/整理后的结果.md
index b6ec30ec..b84bda6b 100644
--- a/dsLightRag/ShiTi/Res/整理后的结果.md
+++ b/dsLightRag/ShiTi/Res/整理后的结果.md
@@ -1,61 +1,49 @@
-### 题目1
-**题目序号**: 1  
-**题目内容**: 已知集合 $A=\left\{x \mid -5 < x^{3} < 5\right\}, B=\left\{-3,-1,0,2,3\right\}$，则 $A \cap B=$  
-**选项**:  
-A. $\{-1,0\}$  
-B. $\{2,3\}$  
-C. $\{-3,-1,0\}$  
-D. $\{-1,0,2\}$  
-**答案**: A  
-**解析**: $A \cap B=\{-1,0\}$，选 A。
-
----
-
-### 题目2
-**题目序号**: 2  
-**题目内容**: 若 $\frac{2}{z-1}=1+i$，则 $z=$  
-**选项**:  
-A. $-1-i$  
-B. $-1+i$  
-C. $1-i$  
-D. $1+i$  
-**答案**: C  
-
----
-
-### 题目3
-**题目序号**: 3  
-**题目内容**: 已知向量 $\vec{a}=(0,1)$，$\vec{b}=(2,x)$，若 $\vec{b} \perp (\vec{b}-4\vec{a})$，则 $x=$  
-**选项**:  
-A. $-2$  
-B. $-1$  
-C. $1$  
-D. $2$  
-**答案**: D  
-**解析**: $\vec{b}-4\vec{a}=(2,x-4)$，$\vec{b} \perp (\vec{b}-4\vec{a})$，$\therefore \vec{b}(\vec{b}-4\vec{a})=0$，$\therefore 4+x(x-4)=0$，$\therefore x=2$，选 D。
-
----
-
-### 题目4
-**题目序号**: 4  
-**题目内容**: 已知 $\cos(\alpha+\beta)=m$，$\tan \alpha \tan \beta=2$，则 $\cos(\alpha-\beta)=$  
-**选项**:  
-A. $-3m$  
-B. $-\frac{m}{3}$  
-C. $\frac{m}{3}$  
-D. $3m$  
-**答案**: A  
-**解析**: $\left\{\begin{array}{l}\cos \alpha \cos \beta-\sin \alpha \sin \beta=m \\\frac{\sin \alpha \sin \beta}{\cos \alpha \cos \beta}=2\end{array}\right.$，$\therefore \left\{\begin{array}{l}\sin \alpha \sin \beta=-2m \\\cos \alpha \cos \beta=-m\end{array}\right.$ $\cos(\alpha-\beta)=\cos \alpha \cos \beta+\sin \alpha \sin \beta=-m-2m=-3m$，选 A。
-
----
-
-### 题目5
-**题目序号**: 5  
-**题目内容**: 已知圆柱和圆锥的底面半径相等，侧面积相等，且它们的高均为 $\sqrt{3}$，则圆锥的体积为  
-**选项**:  
-A. $2\sqrt{3}\pi$  
-B. $3\sqrt{3}\pi$  
-C. $6\sqrt{3}\pi$  
-D. $9\sqrt{3}\pi$  
-**答案**: B  
-**解析**: 设它们底面半径为 $r$，圆锥母线 $l$，$\therefore 2\pi r\sqrt{3}=\pi rl$，$\therefore l=\sqrt{3}$，则圆锥的体积为 $\frac{1}{3}\pi r^{2}h$。
\ No newline at end of file
+1. 题目序号：1
+2. 题目内容：已知集合 $A=\left\{x \mid -5 < x^{3} < 5\right\}, B=\left\{-3,-1,0,2,3\right\}$，则 $A \cap B=$
+3. 选项：
+   A. $\{-1,0\}$
+   B. $\{2,3\}$
+   C. $\{-3,-1,0\}$
+   D. $\{-1,0,2\}$
+4. 答案：A
+5. 解析：$A \cap B=\{-1,0\}$，选 A。
+
+1. 题目序号：2
+2. 题目内容：若 $\frac{2}{z-1}=1+i$，则 $z=$
+3. 选项：
+   A. $-1-i$
+   B. $-1+i$
+   C. $1-i$
+   D. $1+i$
+4. 答案：C
+5. 解析：
+
+1. 题目序号：3
+2. 题目内容：已知向量 $\vec{a}=(0,1)$，$\vec{b}=(2,x)$，若 $\vec{b} \perp (\vec{b}-4\vec{a})$，则 $x=$
+3. 选项：
+   A. $-2$
+   B. $-1$
+   C. $1$
+   D. $2$
+4. 答案：D
+5. 解析：$\vec{b}-4\vec{a}=(2,x-4)$，$\vec{b} \perp (\vec{b}-4\vec{a})$，$\therefore \vec{b}(\vec{b}-4\vec{a})=0$，$\therefore 4+x(x-4)=0$，$\therefore x=2$，选 D。
+
+1. 题目序号：4
+2. 题目内容：已知 $\cos(\alpha+\beta)=m$，$\tan \alpha \tan \beta=2$，则 $\cos(\alpha-\beta)=$
+3. 选项：
+   A. $-3m$
+   B. $-\frac{m}{3}$
+   C. $\frac{m}{3}$
+   D. $3m$
+4. 答案：A
+5. 解析：$\left\{\begin{array}{l}\cos \alpha \cos \beta-\sin \alpha \sin \beta=m \\\frac{\sin \alpha \sin \beta}{\cos \alpha \cos \beta}=2\end{array}\right.$，$\therefore \left\{\begin{array}{l}\sin \alpha \sin \beta=-2m \\\cos \alpha \cos \beta=-m\end{array}\right.$，$\cos(\alpha-\beta)=\cos \alpha \cos \beta+\sin \alpha \sin \beta=-m-2m=-3m$，选 A。
+
+1. 题目序号：5
+2. 题目内容：已知圆柱和圆锥的底面半径相等，侧面积相等，且它们的高均为 $\sqrt{3}$，则圆锥的体积为
+3. 选项：
+   A. $2\sqrt{3}\pi$
+   B. $3\sqrt{3}\pi$
+   C. $6\sqrt{3}\pi$
+   D. $9\sqrt{3}\pi$
+4. 答案：B
+5. 解析：设它们底面半径为 $r$，圆锥母线 $l$，$\therefore 2\pi r\sqrt{3}=\pi rl$，$\therefore l=\sqrt{3}$，则圆锥的体积为 $\frac{1}{3}\pi r^{2}h$。
\ No newline at end of file
diff --git a/dsLightRag/ShiTi/T4_DocxToMd.py b/dsLightRag/ShiTi/T3_DocxToMd.py
similarity index 92%
rename from dsLightRag/ShiTi/T4_DocxToMd.py
rename to dsLightRag/ShiTi/T3_DocxToMd.py
index 2e372b01..8265946d 100644
--- a/dsLightRag/ShiTi/T4_DocxToMd.py
+++ b/dsLightRag/ShiTi/T3_DocxToMd.py
@@ -3,7 +3,7 @@ import os
 import shutil
 
 from raganything import RAGAnything, RAGAnythingConfig
-from Util.RagUtil import create_llm_model_func, create_vision_model_func, create_embedding_func
+from Util.LightRagUtil import create_llm_model_func, create_embedding_func, create_vision_model_func
 
 import logging
 
@@ -24,10 +24,10 @@ logger.addHandler(handler)
 async def main():
     # 要处理的文件路径
     file_path = "Docx/《动能定理》巩固练习.docx"
-    WORKING_DIR = "../../Topic/MathOcr"
+    WORKING_DIR = "../Topic/MathOcr"
 
     # 删除output目录下的所有文件
-    output_dir = "../../output"
+    output_dir = "../output"
     shutil.rmtree(output_dir, ignore_errors=True)
     os.makedirs(output_dir, exist_ok=True)
 
diff --git a/dsLightRag/Util/LightRagUtil.py b/dsLightRag/Util/LightRagUtil.py
index 02555828..7524dbe4 100644
--- a/dsLightRag/Util/LightRagUtil.py
+++ b/dsLightRag/Util/LightRagUtil.py
@@ -139,4 +139,43 @@ def create_embedding_func():
             api_key=EMBED_API_KEY,
             base_url=EMBED_BASE_URL,
         ),
-    )
\ No newline at end of file
+    )
+
+
+def create_vision_model_func(llm_model_func):
+    def vision_model_func(
+            prompt, system_prompt=None, history_messages=[], image_data=None, **kwargs
+    ):
+        if image_data:
+            return openai_complete_if_cache(
+                VISION_MODEL_NAME,
+                "",
+                system_prompt=None,
+                history_messages=[],
+                messages=[
+                    {"role": "system", "content": system_prompt}
+                    if system_prompt
+                    else None,
+                    {
+                        "role": "user",
+                        "content": [
+                            {"type": "text", "text": prompt},
+                            {
+                                "type": "image_url",
+                                "image_url": {
+                                    "url": f"data:image/jpeg;base64,{image_data}"
+                                },
+                            },
+                        ],
+                    }
+                    if image_data
+                    else {"role": "user", "content": prompt},
+                ],
+                api_key=VISION_API_KEY,
+                base_url=VISION_BASE_URL,
+                **kwargs,
+            )
+        else:
+            return llm_model_func(prompt, system_prompt, history_messages, **kwargs)
+
+    return vision_model_func
\ No newline at end of file
diff --git a/dsLightRag/Util/__pycache__/LightRagUtil.cpython-310.pyc b/dsLightRag/Util/__pycache__/LightRagUtil.cpython-310.pyc
index cca97fca..f3a1e61a 100644
Binary files a/dsLightRag/Util/__pycache__/LightRagUtil.cpython-310.pyc and b/dsLightRag/Util/__pycache__/LightRagUtil.cpython-310.pyc differ