From 1ecd82f96e00eb42f99133110527ff1a76423804 Mon Sep 17 00:00:00 2001 From: HuangHai <10402852@qq.com> Date: Thu, 10 Jul 2025 13:02:02 +0800 Subject: [PATCH] 'commit' --- dsLightRag/ShiTi/T2_QWenOcr.py | 3 +- dsLightRag/Util/LightRagUtil.py | 2 - .../output/数学OCR整理后的结果.md | 49 +++++++++++++++++++ 3 files changed, 50 insertions(+), 4 deletions(-) create mode 100644 dsLightRag/output/数学OCR整理后的结果.md diff --git a/dsLightRag/ShiTi/T2_QWenOcr.py b/dsLightRag/ShiTi/T2_QWenOcr.py index 3f776fe7..afe6389a 100644 --- a/dsLightRag/ShiTi/T2_QWenOcr.py +++ b/dsLightRag/ShiTi/T2_QWenOcr.py @@ -29,6 +29,5 @@ completion = client.chat.completions.create( ocr_text = completion.choices[0].message.content # 二、调用格式化函数处理内容 -formatted_content = format_exam_content(client=client, raw_text=ocr_text, - output_path="../output/数学OCR整理后的结果.md") +format_exam_content(client=client, raw_text=ocr_text, output_path="../output/数学OCR整理后的结果.md") print("保存成功!") diff --git a/dsLightRag/Util/LightRagUtil.py b/dsLightRag/Util/LightRagUtil.py index 3925c356..4771ae88 100644 --- a/dsLightRag/Util/LightRagUtil.py +++ b/dsLightRag/Util/LightRagUtil.py @@ -223,5 +223,3 @@ def format_exam_content(client, raw_text, output_path): with open(output_path, "w", encoding="utf-8") as f: f.write(formatted_content) - - return formatted_content \ No newline at end of file diff --git a/dsLightRag/output/数学OCR整理后的结果.md b/dsLightRag/output/数学OCR整理后的结果.md new file mode 100644 index 00000000..3e4f5f0a --- /dev/null +++ b/dsLightRag/output/数学OCR整理后的结果.md @@ -0,0 +1,49 @@ +1. 题目序号:1 +2. 题目内容:已知集合 $A=\left\{x \mid -5 < x^{3} < 5\right\}, B=\left\{-3,-1,0,2,3\right\}$,则 $A \cap B=$ +3. 选项: + A. $\{-1,0\}$ + B. $\{2,3\}$ + C. $\{-3,-1,0\}$ + D. $\{-1,0,2\}$ +4. 答案:A +5. 解析:$A \cap B=\{-1,0\}$,选 A。 + +1. 题目序号:2 +2. 题目内容:若 $\frac{2}{z-1}=1+i$,则 $z=$ +3. 选项: + A. $-1-i$ + B. $-1+i$ + C. $1-i$ + D. $1+i$ +4. 答案:C +5. 解析:无 + +1. 题目序号:3 +2. 题目内容:已知向量 $\vec{a}=(0,1)$,$\vec{b}=(2,x)$,若 $\vec{b} \perp (\vec{b}-4\vec{a})$,则 $x=$ +3. 选项: + A. $-2$ + B. $-1$ + C. $1$ + D. $2$ +4. 答案:D +5. 解析:$\vec{b}-4\vec{a}=(2,x-4)$,$\vec{b} \perp (\vec{b}-4\vec{a})$,$\therefore \vec{b}(\vec{b}-4\vec{a})=0$,$\therefore 4+x(x-4)=0$,$\therefore x=2$,选 D。 + +1. 题目序号:4 +2. 题目内容:已知 $\cos(\alpha+\beta)=m$,$\tan \alpha \tan \beta=2$,则 $\cos(\alpha-\beta)=$ +3. 选项: + A. $-3m$ + B. $-\frac{m}{3}$ + C. $\frac{m}{3}$ + D. $3m$ +4. 答案:A +5. 解析:$\left\{\begin{array}{l}\cos \alpha \cos \beta-\sin \alpha \sin \beta=m \\\frac{\sin \alpha \sin \beta}{\cos \alpha \cos \beta}=2\end{array}\right.$,$\therefore \left\{\begin{array}{l}\sin \alpha \sin \beta=-2m \\\cos \alpha \cos \beta=-m\end{array}\right.$,$\cos(\alpha-\beta)=\cos \alpha \cos \beta+\sin \alpha \sin \beta=-m-2m=-3m$,选 A。 + +1. 题目序号:5 +2. 题目内容:已知圆柱和圆锥的底面半径相等,侧面积相等,且它们的高均为 $\sqrt{3}$,则圆锥的体积为 +3. 选项: + A. $2\sqrt{3}\pi$ + B. $3\sqrt{3}\pi$ + C. $6\sqrt{3}\pi$ + D. $9\sqrt{3}\pi$ +4. 答案:B +5. 解析:设它们底面半径为 $r$,圆锥母线 $l$,$\therefore 2\pi r\sqrt{3}=\pi rl$,$\therefore l=\sqrt{3}$,则圆锥的体积为 $\frac{1}{3}\pi r^{2}h$。 \ No newline at end of file