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from openpyxl import load_workbook
def column_letter_to_number ( column_letter ) :
"""
将 Excel 列字母转换为数字
:param column_letter: 列字母，如 " A " , " B " , " Z " , " AA " , " AB " 等
:return: 列数字， 例如 " A " 返回 1, " B " 返回 2
"""
result = 0
for i , letter in enumerate ( reversed ( column_letter ) ) :
result + = ( ord ( letter ) - ord ( ' A ' ) + 1 ) * ( 26 * * i )
return result
# 输入文件路径
xlsx_file = r ' D: \ dsWork \ 2025年收集的人口与教育数据库（ ） \ 2015-2020年的数据 \ 基础教育 \ 2019.xlsx '
sheet_name = ' 基教小学 '
# 从第 8 行开始是有效数据
row_start = 8
# 定义列索引（列索引从 1 开始）
col_school_name = 2 # B 列：学校名称
col_school_type = 4 # D 列：办学类型
col_school_count = 6 # F 列：学校数量
# 加载 Excel 文件
wb = load_workbook ( xlsx_file )
ws = wb [ sheet_name ]
col_city = column_letter_to_number ( ' MM4 ' ) # MM4 列：市
col_district = column_letter_to_number ( ' MN4 ' ) # MN4 列：区
# 遍历有效数据行并输出指定列的值
# for row in ws.iter_rows(min_row=row_start, values_only=True):
# school_name = row[col_school_name - 1] # B 列：学校名称
# school_type = row[col_school_type - 1] # D 列：办学类型
# school_count = row[col_school_count - 1] # F 列：学校数量
# city = row[col_city - 1] # MM 列：市
# district = row[col_district - 1] # MN 列：区
#
# if school_count > 0:
# # 打印指定列的值
# print(f"学校名称: {school_name}, 办学类型: {school_type}, 学校数量: {school_count}, 市: {city}, 区: {district}")
# 关闭 Excel 文件
ws . close ( )
wb . close ( )
