'commit'

AI/Neo4j/K2_Neo4jExecutor.py

@@ -4,6 +4,7 @@ import re
 from Util import *
 from Config import *
 
+
 class K2_Neo4jExecutor:
     def __init__(self, uri, auth):
         self.graph = Graph(uri, auth=auth)
@@ -57,7 +58,7 @@ class K2_Neo4jExecutor:
             return stats
 
 
-if __name__ == '__main__':
+def init():
     executor = K2_Neo4jExecutor(
         uri=NEO4J_URI,
         auth=NEO4J_AUTH
@@ -85,3 +86,6 @@ if __name__ == '__main__':
     f = "优化.cypher"
     executor.execute_cypher_file(f)
 
+
+if __name__ == '__main__':
+    init()

AI/Neo4j/K3_Start.py

@@ -1,21 +1,43 @@
 from K1_KnowledgeGraph import *
 from K2_Neo4jExecutor import *
 
+
+# 切割试题
+def split_questions(file_path):
+    with open(file_path, 'r', encoding='utf-8') as f:
+        content = f.read()
+
+    # 使用正则表达式匹配题目块（包含答案）
+    pattern = r'(\d+\.\s+【.*?】.*?(?=\n\d+\.|\Z))'
+    questions = re.findall(pattern, content, re.DOTALL)
+
+    # 清洗每个题目块的空白字符
+    cleaned_questions = [q.strip() for q in questions]
+
+    return cleaned_questions[:10]  # 确保只返回前10题
+
+
 if __name__ == '__main__':
+    # 清库
+    init()
+
     # 准备执行
     executor = K2_Neo4jExecutor(
         uri=NEO4J_URI,
         auth=NEO4J_AUTH
     )
+    # 使用示例
+    question_blocks = split_questions('ShiTi.md')
 
-    # 测试用例
-    test_content = '''
-       题目：一个长方体的长是8厘米，宽是5厘米，高是3厘米，求它的表面积是多少平方厘米？
-       '''
-    try:
-        kg = KnowledgeGraph(test_content)
-        success, cypher = kg.run()
-        res = executor.execute_cypher_text(cypher)
-        print("恭喜，执行数据插入完成！")
-    except Exception as e:
-        print(f"程序初始化失败: {str(e)}")
+    # 验证分割结果
+    for i, block in enumerate(question_blocks, 1):
+        print(f"第{i}题块：")
+        print("-" * 50)
+        try:
+            kg = KnowledgeGraph(block)
+            success, cypher = kg.run()
+            print(cypher)
+            res = executor.execute_cypher_text(cypher)
+            print("恭喜，执行数据插入完成！")
+        except Exception as e:
+            print(f"程序初始化失败: {str(e)}")

AI/Neo4j/ShiTi.md

@@ -0,0 +1,32 @@
+### 三年级
+1. 【购物计算】小明用50元买了3本笔记本，每本8元，还剩多少钱？
+   - 答案：50 - 3×8 = 26元
+
+2. 【乘法应用】学校食堂每天消耗15袋大米，一周（5天）需要准备多少袋？
+   - 答案：15×5 = 75袋
+
+3. 【周长计算】一个正方形花坛边长3米，要在四周围栅栏，需要多长的栅栏？
+   - 答案：3×4 = 12米
+
+### 四年级
+4. 【四则运算】图书馆原有图书1250本，上午借出368本，下午归还195本，现有多少本？
+   - 答案：1250 - 368 + 195 = 1077本
+
+5. 【面积问题】长方形果园长25米，宽比长短7米，这个果园的面积是多少？
+   - 答案：25×(25-7) = 450平方米
+
+6. 【时间问题】甲乙两车从相距240公里的两地同时出发相向而行，甲车时速60公里，乙车时速40公里，几小时后相遇？
+   - 答案：240÷(60+40) = 2.4小时
+
+### 五年级
+7. 【分数运算】果汁店第一天卖出3/4吨橙汁，第二天卖出1/2吨苹果汁，两天共卖出多少吨？
+   - 答案：3/4 + 1/2 = 5/4吨
+
+8. 【小数应用】文具店钢笔单价12.5元，买4支送1支，买20支实际要付多少钱？
+   - 答案：(20÷5)×4×12.5 = 200元
+
+9. 【体积计算】长方体游泳池长25米，宽12米，深1.8米，这个游泳池最多能装多少立方米水？
+   - 答案：25×12×1.8 = 540立方米
+
+10. 【比例问题】妈妈给小明和妹妹36元零花钱，按5:4分配，小明能得多少元？
+    - 答案：36÷(5+4)×5 = 20元

AI/Neo4j/knowledge_graph.cypher

@@ -1,15 +0,0 @@
-CREATE CONSTRAINT IF NOT EXISTS FOR (kp:KnowledgePoint) REQUIRE kp.id IS UNIQUE;
-CREATE CONSTRAINT IF NOT EXISTS FOR (ab:AbilityPoint) REQUIRE ab.id IS UNIQUE;
-MERGE (kp1:KnowledgePoint {id: "KP_e99a18", name: "周长计算", level: "小学"});
-MERGE (kp2:KnowledgePoint {id: "KP_5d4140", name: "图形拼接", level: "小学"});
-MERGE (ab1:AbilityPoint {id: "AB_e99a18", name: "图形理解", category: "空间想象"});
-MERGE (ab2:AbilityPoint {id: "AB_5d4140", name: "数学运算", category: "计算"});
-MERGE (q:Question {id: "66c060a1", content: "通过7个小长方形拼成的大长方形的周长计算", difficulty: 2});
-MATCH (q:Question {id: "66c060a1"}), (kp1:KnowledgePoint {id: "KP_e99a18"})
-MERGE (q)-[:TESTS_KNOWLEDGE {weight: 0.8}]->(kp1);
-MATCH (q:Question {id: "66c060a1"}), (kp2:KnowledgePoint {id: "KP_5d4140"})
-MERGE (q)-[:TESTS_KNOWLEDGE {weight: 0.6}]->(kp2);
-MATCH (q:Question {id: "66c060a1"}), (ab1:AbilityPoint {id: "AB_e99a18"})
-MERGE (q)-[:REQUIRES_ABILITY {weight: 0.7}]->(ab1);
-MATCH (q:Question {id: "66c060a1"}), (ab2:AbilityPoint {id: "AB_5d4140"})
-MERGE (q)-[:REQUIRES_ABILITY {weight: 0.9}]->(ab2);