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from openpyxl import load_workbook
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def column_letter_to_number(column_letter):
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"""
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将 Excel 列字母转换为数字
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:param column_letter: 列字母，如 "A", "B", "Z", "AA", "AB" 等
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:return: 列数字， 例如 "A" 返回 1, "B" 返回 2
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"""
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result = 0
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for i, letter in enumerate(reversed(column_letter)):
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result += (ord(letter) - ord('A') + 1) * (26 ** i)
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return result
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# 输入文件路径
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xlsx_file = r'D:\dsWork\2025年收集的人口与教育数据库（20250328）\2015-2020年的数据\基础教育\2019.xlsx'
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sheet_name = '基教小学'
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# 从第 8 行开始是有效数据
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row_start = 8
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# 定义列索引（列索引从 1 开始）
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col_school_name = 2 # B 列：学校名称
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col_school_type = 4 # D 列：办学类型
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col_school_count = 6 # F 列：学校数量
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# 加载 Excel 文件
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wb = load_workbook(xlsx_file)
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ws = wb[sheet_name]
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col_city = column_letter_to_number('MM4') # MM4 列：市
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col_district = column_letter_to_number('MN4') # MN4 列：区
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# 遍历有效数据行并输出指定列的值
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# for row in ws.iter_rows(min_row=row_start, values_only=True):
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# school_name = row[col_school_name - 1] # B 列：学校名称
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# school_type = row[col_school_type - 1] # D 列：办学类型
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# school_count = row[col_school_count - 1] # F 列：学校数量
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# city = row[col_city - 1] # MM 列：市
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# district = row[col_district - 1] # MN 列：区
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#
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# if school_count > 0:
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# # 打印指定列的值
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# print(f"学校名称: {school_name}, 办学类型: {school_type}, 学校数量: {school_count}, 市: {city}, 区: {district}")
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# 关闭 Excel 文件
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ws.close()
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wb.close()
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